Question

find a quadratic polynomial whose zeroes are -9 and -9/1

8 points
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and for the correct answer ​

Answer 1

Answer:

The quadratic equation will be x²+9x-9

Answer 2

$\textit{\underline{\large{\underline{\red{Answer:-}}}}}$

$\mathrm{\boxed{\implies{\pink{x^{2}+18x+81}}}}$

$\textit{\underline{\large{\underline{\green{Step by step Explanation:-:-}}}}}$

$\textit{\underline{Check,,}}$

$\mathtt{x^{2}+18x+81}$

$\mathtt{(a=1,,b=18,,c=81)}$

$\mathtt{b^{2}-4ac}$

$\mathtt{=18^{2}-4\times{1}\times{81}}$

$\mathtt{=324-324}$

$\mathtt{=0}$

because,,$\mathtt{b^{2}-4ac=0}$

$\textit{\underline{Hence,,}}$

$\mathtt{x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}}$

$\mathtt{=\frac{-18\pm\sqrt{0}}{2\times{1}}}$

$\mathtt{=\frac{-18\pm{0}}{2}}$

$\mathtt{x=\frac{-18+0}{2}}$

$\mathtt{=\frac{-18}{2}}$

$\mathtt{=-9}$

$\mathtt{Or,, x=\frac{-18-0}{2}}$

$\mathtt{=\frac{-18}{2}}$

$\mathtt{=-9 or,,\frac{-9}{1}}$

$\textit{\underline{Hence,,}}$

$\mathrm{\boxed{\implies{\pink{x=-9 or,,\frac{-9}{1}}}}}$

so the zeros are -9 and-9/1..

$\textbf{\underline{Hence proved}}$

❣️❣️✌️✌️ Hope it helps you.. please mark it as Brainliest answer... thanks..❣️❣️✌️✌️