find a quadratic polynomial whose zeroes are a and b satisfying the relation a+b=3 and a-b=1
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Answered by
6
a=2andb=1
x^2-3x+2=0 is required quadratic equation
x^2-3x+2=0 is required quadratic equation
Answered by
27
Hiii friend,
A + B = 3---------(1)
A - B = 1------------(2)
From equation (1) we get,
A + B = 3
A = 3-B---------(3)
Putting the value of A in equation (2)
A - B = 1
3-B - B = 1
-2B = 1-3
-2B = -2
B = -2/-2 => 1
Putting the value of B in equation (3)
A = 3-B => 3-1 = 2
Therefore,
2 and 1 are the two zeroes.
Let Alpha = 2 and beta = 1
Sum of zeroes = (Alpha + Beta) = (2+1) = 3
Product of zeroes = (Alpha × Beta) = (2 × 1) = 2
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes.
=> X² -(3)X + 2
=> X²-3X+2
HOPE IT WILL HELP YOU....... :-)
A + B = 3---------(1)
A - B = 1------------(2)
From equation (1) we get,
A + B = 3
A = 3-B---------(3)
Putting the value of A in equation (2)
A - B = 1
3-B - B = 1
-2B = 1-3
-2B = -2
B = -2/-2 => 1
Putting the value of B in equation (3)
A = 3-B => 3-1 = 2
Therefore,
2 and 1 are the two zeroes.
Let Alpha = 2 and beta = 1
Sum of zeroes = (Alpha + Beta) = (2+1) = 3
Product of zeroes = (Alpha × Beta) = (2 × 1) = 2
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes.
=> X² -(3)X + 2
=> X²-3X+2
HOPE IT WILL HELP YOU....... :-)
Mylo2145:
thanku very much .....
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