find a quadratic polynomial, whose zeroes are root of 2 and -3/2 respectively. also find the zeroes
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2
Answer:
I had attached a pic which contains the solution of this question.
Step-by-step explanation:
Pic 1 alters the question to "zeroes are 2 and -3/2"
Pic 2 depicts your own question. zeroes are √2 and i√3/√2
Thanks.
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Answered by
0
Answer:
x²+(3-2√2)x/2 -3/√2
Step-by-step explanation:
polynomial
=> x²-(sum) x+ ( product)
x²- ( √2-3/2) x + (√2×-3/2)
= x²+ (3-2√2)x/2- 3/√2
zeroes are already given in the question
these are (1) √2 and (2) -3/2
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