Math, asked by ldragonsaha, 2 months ago

Find a quadratic polynomial whose zeroes are the least and the greatest square natural
numbers of two digits.

.
.pls give more than 1 correct answer so that i can mark brainlieist ​

Answers

Answered by pulakmath007
2

SOLUTION

TO DETERMINE

The quadratic polynomial whose zeroes are the least and the greatest square natural numbers of two digits.

CONCEPT TO BE IMPLEMENTED

If the Sum of zeroes and Product of the zeroes of a quadratic polynomial is given then the quadratic polynomial is

 \sf{ {x}^{2}  -(Sum  \: of \:  the \: zeroes )x +  Product \:  of  \: the \:  zeroes }

EVALUATION

We have to find the quadratic polynomial whose zeroes are the least and the greatest square natural numbers of two digits.

Now the least and the greatest square natural numbers of two digits are 16 and 81 respectively

So sum of the zeroes = 16 + 81 = 97

Product of the Zeroes = 16 × 81 = 1296

So the required Quadratic polynomial is

 \sf{ {x}^{2}  -(Sum  \: of \:  the \: zeroes )x +  Product \:  of  \: the \:  zeroes }

 =  \sf{ {x}^{2} - 97x + 1296 }

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