Question

find a quadratic polynomial whose zeroes exceeds the zeroes of x^2 +5x +6 by a number 2​

Answer 1

Step-by-step explanation:

x²+5x+6

=x²+(2+3)x+2×3

=(x+2)(x+3)

so zeroes of the polynomial are -2 and-3

Now zeroes of the new polynomial are 0 and -1

so the polynomial is

x²-(-1+0)x+(-1)×0

=x²+x.(Answer)