Question

Find a quadratic polynomial whose zeros are 2 +√3 and 2 - √3​

Answer 1

Step-by-step explanation:

I hope that your answer

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Answer 2

Answer: given the zeroes are 2+root 3 and 2-root 3

Step-by-step explanation:

now the general formula for a quadratic polynomial is $x^{2} -(\alpha +\beta)x+\alpha \beta$

then $\alpha$= 2+$\sqrt{3$

       $\beta$= 2-$\sqrt{3}$

then $\alpha +\beta = 2+\sqrt{3} +(2-\sqrt{3} )=4\\ \alpha \beta = (2+\sqrt{3}) *(2-\sqrt{3} )=1\\substitute in the general form\\then,\\ x^{2} - 4x +1$