Question

find a quadratic polynomial whose zeros are -2/root 3 and root 3/4

Answer 1

Is this your answer??

Answer 2

let
$- 2 \div \sqrt{3}$
is
$\alpha$
and
$\sqrt{3 } \div 4$
is
$\beta$
now we know that,
quadratic polynomial formula...

$x {}^{2} - ( \alpha + \beta )x + \alpha \beta$
:. -2/root3+root 3/4=-5/4 root3

and
-2/root3×root3/4=-1/2

now put the values in given formula..

the ans is...
${x}^{2} + \frac{ 5}{4} \sqrt{3} - \frac{1}{2}$


hope it helps you...
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