Question

Find a quadratic polynomial whose zeros are
3/√2and-1/√2​

Answer 1

$\bf{Answer\colon}$

$\begin{gathered}Zeros\:of\:polynomial\\=3+\sqrt{2}\:and\:3-\sqrt{2}\\Sum\:of\:zeros\\=3+\cancel{\sqrt{2}}+3-\cancel{\sqrt{2}}\\=6\\Product\:of\:zeros\\=(3+\sqrt{2})(3-\sqrt{2})\\={(3)}^{2}-{(\sqrt{2})}^{2}\\=9-2\\=7\\Now,\\Quadratic\:polynomial\\= > {x}^{2}-Sx+P=0\\= > {x}^{2}-6x+7=0\end{gathered}$

$\begin{gathered}Therefore,required\:polynomial\\= > {x}^{2}-6x+7=0\end{gathered}$

Answer 2

Step-by-step explanation:

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