Question

find a quadratic polynomial whose zeros are -3 and 2

Answer 1

α=-3 , β=2

αβ = -3×2=-6

α+β =-3+2=-1

f(x)= x² - (α+β)x + αβ

Hence,f(x) = x² + x - 6.
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Answer 2

Sum of zeros=-3+2=-1
product of zeros =(-3)(2)=-6
quadratic polynomial will be
$x^{2} - (sum \: of \: zero \:)x + \: ( product \: of \: zeros) \\ x^{2} - ( - 1x) + ( - 6) \\ x ^{2} + x - 6$