Question

find a quadratic polynomial , whose zeros are -3 and 4​

Answer 1

GIVEN :-

• The zeros of quadratic polynomial are -3 and 4.

TO FIND :-

• The quadratic polynomial.

SOLUTUON :-

As we know that , for finding the zeros of the polynomial , the polynomial must be equal to zero , so we can say that,

➳ (x - 4)(x + 3) = 0

➳ (x - 4) = 0 , (x + 3) = 0

➳ x = 4 , x = -3

Hence we satisfied the given zeros of the polynomial.

✮ Required quadratic polynomial,

➵ (x - 4)(x + 3)

➵ x(x + 3) - 4(x + 3)

➵ x² + 3x - 4x - 12

➵ x² - x - 12.

Hence the required quadratic polynomial is x² - x - 12.

Answer 2

Given :-

• The zeros of quadratic polynomial is -3 and 4.

To Find :-

• The Quadratic polynomial.

Solution :-

$\to\sf{(x - 4)(x + 3) = 0}$

$\to\sf{(x - 4) = 0, \: (x + 3) = 0}$

$\to\sf{x = 4, \: x = -3}$

• The zeros of quadratic polynomial = 4 and -3.

Now,

$\to\sf{(x - 4)(x + 3)}$

$\to\sf{x(x + 3) - 4(x + 3)}$

$\to\sf{ {x}^{2} + 3x - 4x - 12}$

$\to\sf{ {x}^{2} - x - 12}$

Hence,

• The Quadratic polynomial = x² - x - 12.