Question

find a quadratic polynomial whose zeros are -4 and 1 respectively​

Answer 1

Answer:

S=-4+1=-3

P=-4×1=-4

so by putting value of S and P I,

x²-Sx+P

x²-(-3)x+(-4)

x²+3x-4 hence quadratic equation is x²+3x-4.

Answer 2

Answer:

$x^{2} +3x-4$ is the required polynomial.

Step-by-step explanation:

If  $\alpha$ and $\beta$ are the roots of any quadratic polynomial than quadratic polynomial can be expressed as

                                           $= (x-\alpha )(x-\beta )$

                                         $=x^{2} -(\alpha +\beta )x+\alpha \beta$

Here,$\alpha =-4, \beta =1$

subsituting these values, we get

Required Quadratic Polynomial

                                 $= (x-(-4))(x-1)\\=(x+4)(x-1)\\=x^{2} +3x-4$

Therefore, required polynomial is $x^{2} +3x-4$.

  #SPJ2