Question

Find a quadratic polynomial whose zeros are – 9 and -1/9.

Answer 1

Answer:

let alpha =-9

let beta = -1/9

alpha +beta = -9+(-1/9)

=-9-1/9

=-81-1/9

=-80/9

alpha ×beta =1

quadratic polynomial= x²-(alpha+beta)x+alpha×beta

x² +80/9x+1

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Answer 2

Answer:

if one root is α=-9 and another is β=-1/9

now quadratic formula is in the form ax²+bx+c

ax²+(α+β)x+αβ=0

ax²+(-9+-1/9)+(-9×-1/9)=0

x²+(-82/9)x+1=0

NOW WE WANT TO SIMPLIFY THIS EQUATION

SO

multiply the eqn with 9

9x²+(-82)x+9=0

9x²-82x+9=0

therefore this is your answer

Step-by-step explanation: