Question

find a quadratic polynomial whose zeros are double the zeros of x square minus x minus 6​

Answer 1

Step-by-step explanation:

As we have given polynomial,

x² - x - 6 = 0

x² -3x + 2x - 6 = 0

x (x - 3 ) + 2(x - 3 ) = 0

(x + 2) (x - 3) = 0

x = -2 or x = 3

we have to find find a quadratic polynomial whose zeros are double the zeros of x² - x - 6 =0

let the roots of this quadratic equation are α and β

α = 2 (-2) = -4

β = 2 (3) = 6

we know the formula to making a quadratic equation

[ x² - (α + β )x + (α.β)]

x² - (-4 + 6)x + (-4 . 6)

x² - (2)x + (-24)

x² - 2x - 24 = 0

therefor the required quadratic equation is x² - 2x - 24 = 0

Answer 2

Answer:

Step-by-step explanation: