Math, asked by rahulrao7285p8vpne, 1 year ago

Find a quadratic polynomial whose zeros are reciprocal of the zero of polynomial f(x) = ax2+bx+c

Answers

Answered by UnknownDude
283
Let the roots of the above equation be alpha and beta. Then the roots of the new equation will be 1/alpha and 1/beta.
In the first equation...
 \alpha  +  \beta  =  -  \frac{b}{a}  \\  \alpha  \beta  =  \frac{c}{a}
If roots of an equation are given, the equation will be
 {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta
Which in this case are the reciprocals of the given equation.
So, we will find the sum and product of the reciprocal roots.
 \frac{1}{ \alpha }  +  \frac{1}{ \beta }  =  \frac{ \alpha  +  \beta }{ \alpha  \beta }  \\  =  \frac{  - \frac{b}{a} }{ \frac{c}{a} }  \\  =   - \frac{b}{c}
 \frac{1}{ \alpha }  \times  \frac{1}{ \beta }  =  \frac{1}{ \alpha  \beta }  \\  =  \frac{1}{ \frac{c}{a} }  \\  =  \frac{a}{c}
Now we will put these values in the equation which can be found using roots.
 {x}^{2}  - (  - \frac{b}{c} )x +  \frac{a}{c}  = 0 \\  {x}^{2}  +  \frac{b}{c}  +  \frac{a}{c}  = 0
Multiplying the whole equation by c...
c {x}^{2}  + bx + a = 0
Remember this equation.
If u are asked to give an equation with the roots as reciprocals of the given equation, then juat reverse the order of the coefficients.
The constant becomes the coefficient of x^2.
The coefficient of x^2 becomes the constant.
The coefficient of x remains the same.
Answered by sourasghotekar123
0

Answer:

cx^2 + bx + a.

Step-by-step explanation:

Let p, q be zeros of ax^2+bx+c

therefore p+q=-\frac{b}{a}  and p×q=\frac{c}{a}

Let p and q be zeros of required polynomial

It is given that p = \frac{1}{p}  and q = \frac{1}{q}

Then,

p+q = \frac{1}{p} + \frac{1}{q}

      = \frac{p+q}{p*q}

     = \frac{\frac{-b}{a} }{\frac{c}{a} }

    =-\frac{b}{c}

and  p × q =\frac{1}{p}* \frac{1}{q}

                =\frac{1}{p*q}

               = \frac{a}{c}

therefore,,required polynomial is:

         

                                = x^2 +\frac{b}{c} x + \frac{a}{c}

                        I. e, = cx^2 + bx + a.

QUADRATIC POLYNOMIAL::

       

                                   Quadratic polynomial is a polynomial in which the highest degree monomial is of the second degree. A quadratic polynomial is also known as a second-order polynomial.

The project code is #SPJ2

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