find a quadratic polynomial with -1/4 as the sum and 1/4 as the product of its zeros repectively
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3
Hi there!
We have give that:
Sum = -1/4
Product = 1/4
Now, a general form is x² - (sum)x + (product)
So, x² - ( - 1/4 )x + (1/4) = 0
x² + 1/4x + 1/4 = 0
Take 4 as LCM , we get:
4x² + x + 1 = 0
We have give that:
Sum = -1/4
Product = 1/4
Now, a general form is x² - (sum)x + (product)
So, x² - ( - 1/4 )x + (1/4) = 0
x² + 1/4x + 1/4 = 0
Take 4 as LCM , we get:
4x² + x + 1 = 0
rockakku:
take x as common
the roots are -3 and -4
ok i know dat
this is one
well i need for 4x square +x+1
√D=b²-4ac
√D=(1)²-4*1*4
√D=1-16=-15
x=b+√D/2a. x=1-15/8. x=-7/4
x=b-√D/2a. x=1+15/8. x=2
Answered by
1
p(x)= x^2-(α+β)x+αβ
p(x)=4x^2+x+1
p(x)=4x^2+x+1
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