Find a quadratic polynomial with the given numbers 4 and 1 as the sum and product of zeroes respectively.
Answers
Answered by
1
Answer:
x²-4x+1
Step-by-step explanation:
sum of the zeroes (a+B)=4
product of the zeroes=aB=1
let the quadratic polynomial be
ax²+bx+c
k[x²-(a+B)x+aB],
where K is constant and K is not equal to o then,
K[x²-(4)x+(1)]
If k=1 ,the quadratic polynomial with be
x²-4x+1
Answered by
0
Answer:
= x² -4x + 1
Step-by-step explanation:
Let the polynomial be
p(x) = ax² + bx + c
Sum of zeroes = 4
-b/a = 4
assuming a = 1
-b/1 = 4
b = -4
Product of zeroes = 1
c/a = 1
assuming a = 1
c/1 = 1
c = 1
Now, a = 1, b = -4, c = 1
Hence required quadratic polynomial = ax² + bx + c
= x² +(-4x) + 1
= x² -4x + 1
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