Question

Find a quadratic polynomial with zero – 2 and 1/3​

Answer 1

Required Answer

$\checkmark \tt \: \: \: For \: \: any \: \: quadratic \: \: equation ,$

$\: \: \: \: \: \: \: \tt \: {x}^{2} - (sum \: \: of \: \: roots)x + product \: \: of \: \: roots = 0$

$\large \tt \: Now,$

$\tt \: The \: \: given \: \: zeros \: \: of \: \: the \: \: polynomial \: \: -2 \: \: \& \frac{1}{3}$

$\large \tt Hence,$

$\tt \: the \: \: polynomial \: \: will \: \: be \: \\ \\ \\ \rightsquigarrow \: \tt {x}^{2} - \bigg (\frac{1}{3} + ( - 2) \bigg)x + (\frac{1}{3}) \times ( - 2) = 0 \\ \\ \\ \\ \rightsquigarrow \: \tt x^2 -\bigg(-2+\frac{1}{3}\bigg)x+(-2)\times(\frac{1}{3})=0 \\ \\ \\ \\ \large\therefore \: \: \: \underline {\boxed{ \mathfrak{3 {x}^{2} + 5x - 2 = 0}}}$