Question

find a quadratic polynomial with zeroes -2 and 1/3​

Answer 1

Answer:

$3 {x}^{2} - 5x - 2 = 0$

Step-by-step explanation:

$given,$

$\alpha = - 2$

$\beta = \frac{1}{3}$

$p(x) = {x}^{2} + ( \alpha + \beta )x + \alpha \beta$

$p(x) = {x}^{2} + ( - 2 + \frac{1}{3})x + ( - 2)( \frac{1}{3} )$

${x}^{2} - \frac{5}{3} x - \frac{2}{3}$

$3 {x}^{2} - 5x - 2 = 0$

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Answer 2

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