Question

Find a quadratic polynomial with zeroes -2 and 1/3
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Answer 1

Answer:

2x2 + 5x+3

Step-by-step explanation:

x2-(-1t(-3/2)x + (-1-3/2) = 0

x2 +5/2x+3/2 0

2x 2 +5x +3 = 0(whole multiplied by 2)

As the polynomial structure for quadratic is

x*2-(alpha + beta)x + alpha * beta.

Answer 2

Answer:

x² + $\frac{5x}{3}$  - $\frac{2}{3}$

Step-by-step explanation:

Sum of Zeroes =  $\frac{-5}{3}$

Product of Zeroes = $\frac{-2}{3}$

Therefore,

Quadratic Equation is

(x² - Sum × x +Product)

= x² + $\frac{5x}{3}$  - $\frac{2}{3}$