Find a quadratic polynomial with zeroes 3+root2 and 3-root2
Answers
Answered by
4
let alpha be 3+√2 and bita be 3-√2
alpha+bita = 3+√2+3-√2=6
alpha×bita=(3+√2) (3-√2) =9-2=7
we know, x²-(alpha+bita)x +alpha×bita
x²-6x+7
alpha+bita = 3+√2+3-√2=6
alpha×bita=(3+√2) (3-√2) =9-2=7
we know, x²-(alpha+bita)x +alpha×bita
x²-6x+7
Answered by
3
Answer: please mark it as the brainliest if found helpful
Attachments:
Similar questions