Question

Find a quadratic polynomial with zeros −2 and 1/3.

Answer 1

Dear Student:

Given  A quadratic polynomial with zeros −2 and 1/3.

x=-2 and x=1/3

x+2=0 and x-1/3=0

(x+2)(x-1/3)=0

$x^{2} -\frac{1}{3} x+2x-\frac{2}{3} =0$

$x^{2} +\frac{5}{3}x-\frac{2}{3}=0$

$3x^{2}+5x-2=0$

Hence polynomial is [/tex]$3x^{2}+5x-2$

Hope it helps

Thanks

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Answer 2

HELLO DEAR,

Given  A quadratic polynomial with zeros -2 and 1/3.

x = -2 and x = 1/3

x + 2 = 0 and x - 1/3 = 0

(x + 2)(x - 1/3) = 0

x² - 1/3x + 2x - 2/3 = 0

(3x² - x)/3 + (6x - 2)/3 = 0

3x² - x + 6x - 2 = 0

3x² + 5x - 2 = 0

HENCE ,THE quadratic polynomial if the zeros of it are 2 and -1/3 respectively.
are "3x² + 5x - 2 = 0

I HOPE ITS HELP YOU DEAR,
THANKS