Question

Find a quadratic polynomials , sum of whose zeroes is 2 and product is -8 .hence , find the zeroes of the polynomoals.

Answer 1

Hey friend..!! here's your answer
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By using formula ==>
x^2 - (sum of zeroes)x + (Product of zeroes)
x^2 - (2)x + (-8)
x^2 - 2x - 8 = 0

x^2 - 4x + 2x - 8 =0
x ( x - 4) + 2 ( x -4) = 0
(x + 2) (x - 4)

x = -2 and x = 4

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#Hope its help you dear#
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Answer 2

x^2 - Sx + P = 0
x^2 - 2x + (-8) =0
x^2 - 2x - 8 =0

x^2 -4x + 2x - 8 =0
x ( x- 4) + 2 (x - 4) = 0
(x + 2) (x - 4) = 0

x = -2 or x = 4