Question

find a quadratic whose zeroes are (3+2root2) and (3-2 root 2)​

Answer 1

Answer:

u can easily find by x^2-(add these roots )x+multiply these roots =0

Answer 2

Answer:

x^2 - 6x + 1

Step-by-step explanation:

x^2 (sum)x + (product)

(3 + 2√2) + (3 - 2√2) = 6

(3 + 2√2)

(3 - 2√2) = 3^2 - (2√2)^2

9 - 8 = 1