find a quadric polynomial whose sum and product of zeroes are 0 and √5
Answers
Answer:
x² + √5
Step-by-step explanation:
We must find a Quadratic equation whose Sum = 0 and Product = √5
Let zeroes be a and b
a + b = 0
ab = √5
We know that, such an equation do exist.
and its general formula is
x² - (a + b)x + (ab)
= x² - (0)x + (√5)
= x² + √5
OR
We know that,
Sum of zeroes = -b/a = 0
Product of zeroes = c/a = √5
Now,
Let the Quadratic equation be ax² + bx + c
Let's now divide the whole equation by a, so that the coefficient of x² is 1.
(ax²)/a + (bx)/a + c/a = 0/a
x² + (b/a)x + c/a = 0
We can also write this as,
x² - (-b/a) + (c/a) = 0
Here the -ve's cancel out so it's ok
Now, putting in the values
x² - (0)x + (√5) = 0
x² + √5 = 0
Hence,
x² + √5 is the Quadractic equation whose Sum is 0 and product is √5.
Hope it helped and believing you understood it........All the best