Question

find a quadric polynomial whose zeros are 2, -1/3​

Answer 1

Answer:

3x^2-5x-2

Step-by-step explanation:

2 and -1/3 are the zeroes (Given)

Sum of zeroes = 2+(-1/3)

                         = 5/3

Product of zeroes = 2x(-1/3)

                               = -2/3

Now,

alpha+beta = -b/a = 5/3

 Therefore    b = -5 and a = 3

alpha x beta = c/a = -2/3

Therefore  c = -2 and a = 3

Therefore, Equation = 3x^2-5x-2

Answer 2

Answer:

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