Find a quadttic polynomial the sum of whose zeros is 2 and their product is -8. hence find the zeros of the polynomial
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p(x)=k(x^2-2x-8)
a=1 b=-2 c=-8
alpha+beta=-b/a
=2
alpha×beta=c/a
=-8
a=1 b=-2 c=-8
alpha+beta=-b/a
=2
alpha×beta=c/a
=-8
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