Question

Find a quardinate of a point on X-axis which is equidistant from (2,-5) and (-2, 9).
plz do it fast

Answer 1

the point on x axis be C(x,0)

A(2,-5) AND B(-2,9)

WE KNOW THAT THE DISTANCE BETWEEN AC=BC

SO USING DISTANCE FORMULAE

THE DISTANCE OF AC = ROOT(2-X)^2+ (-5-0)^2

=ROOT(2-X)^2+(-5)^2

= ROOT(2-X)^2 +25

THE DISTANCE BETWEEN BC

=ROOT(-2-X)^2+(9-0)^2

=ROOT(-2-X)^2+(9)^2

=ROOT(-2-X)^2+81

AC=BC

SOBS (squaring on both sides)

(2-x)^2+25= (-2-x)^2+81

=4+X^2-4X+25= 4+X^2+4X+81

=29-4X=85+4X

=-8X=56

=X=-7

THE POINT ON X AXIS IS (-7,0)

HOPE IT HELPS!!!

MARK AS BRAINLIEST