Find a quatric polynomial who's one of the zeroes is - 15 and Simon the zeroes is 42.
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Hiii friend,
One zeros is -15
Let Alpha and beta are the zeros of the polynomial.
Alpha = -15
Sum of zeros = 42
(Alpha + Beta) = 42
-15 + Beta = 42
Beta = 42+15 = 57
Product of zeros = (Alpha × Beta) = (-15 ×57) = -855.
Therefore,
Required Quadratic polynomial = X²-(Alpha+Beta)X + alpha × Beta
=> X²-(42)X+(-855)
=> X²-42X-855
HOPE IT WILL HELP YOU....... :-)
One zeros is -15
Let Alpha and beta are the zeros of the polynomial.
Alpha = -15
Sum of zeros = 42
(Alpha + Beta) = 42
-15 + Beta = 42
Beta = 42+15 = 57
Product of zeros = (Alpha × Beta) = (-15 ×57) = -855.
Therefore,
Required Quadratic polynomial = X²-(Alpha+Beta)X + alpha × Beta
=> X²-(42)X+(-855)
=> X²-42X-855
HOPE IT WILL HELP YOU....... :-)
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