Question

Find a qudratic polynomial whose sum and product of its zeroes are root 3 and 1/2

Answer 1

Answer:

K [2x² - 2√3x + 1]

Step-by-step explanation:

Sum (α+β) = √3

Product (αβ) = 1/2

Polynomial = K [x² - (α+β)x + αβ]

K here is a constant

==: K [x² - (√3)x + 1/2]

==: K [x² - √3x + 1/2]

==: K [2x² - 2√3x + 1]

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Answer 2

Answer:

formula : x^2 + (sum of zeroes) x - ( product of zeroes)

x^2 + root 3x - 1/2 = 0

x^2/1 + root 3x/1 - 1/2 = 0

2x^2 + 2 root 3x -1 /2 = 0

2x^2 + 2 root 3x - 1 = 0*2

so quardic equation = 2x^2 + 2 root 3x - 1