Question

find a rational number between 2/9 and 3/8,and arrange in descending order

Answer 1

2*8/9*8 = 16/72
3*9/8*9 = 27/ 72
so, the rational numbers are - 17*72,18/72,19/72,20/72,21/72,22/72,23/72,24/72,25/72,26/72.

descending order - 26/72,25/72,24/72,23/72,22/72,21/72,20/72,19/72,18/72,17/72.

HOPE IT HELPS........
PLZ MARL AS BRAINLIEST........

Answer 2

A rational number between $\dfrac{2}{9}$ and $\dfrac{3}{8}$ is $\dfrac{17}{72}$.

Descending order: $\dfrac{3}{8},\dfrac{17}{72},\dfrac{2}{9}$

Step-by-step explanation:

Here the given two rational numbers are

$\dfrac{2}{9}=\dfrac{2\times 8}{9\times 8}=\dfrac{16}{72}$

$\dfrac{3}{8}=\dfrac{3\times 9}{8\times 9}=\dfrac{27}{72}$

• where LCM of 9 and 8 is 72

Clearly, 16 < 27 and their denominator is the same. So, there can be many rational numbers between them with the denominator 72 such as

$\dfrac{17}{72},\dfrac{18}{72},\dfrac{19}{72},...,\dfrac{26}{72}$

Then the required descending order is

$\dfrac{3}{8},\dfrac{17}{72},\dfrac{2}{9}$

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