Find a rational number which is 50 times its own logarithm to the base 10.
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Answered by
7
solution:
let, x be rational no.
according to the question, x = 50 × log10 X
x = 100
let, x be rational no.
according to the question, x = 50 × log10 X
x = 100
Configuration:
Yea it seems correct, but i don't know how to explain that, i need the subjective way actually, thx anyways.
Answered by
10
The solution is 100. Just write the equation:
x=50logx
For x=1 you have 1=50×0 which is false.
For x=10 you have 10=50×1 which is false.
For x=100 you have 100=50×2 which is true.
For x=1000 you have 1000=50×3 which is false.
If you don't want to check the options the general way to solve this equation is:
x=50lnxln10
xlnx=50ln10
lnxx=ln1050
e−lnxlnx=ln1050
−e−lnxlnx=−ln1050
Now you apply Lambert's W function which is defined as W(z)eW(z)=z
−lnx=W(−ln1050)
x=e−W(−ln1050)
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