Math, asked by sameena30imam, 1 month ago

find a real positive root of the equation x^3-7x+5=0 using bisection method

Answers

Answered by dipakmandaltutu1973
0

Answer:

Bisection Method Algorithm

Find two points, say a and b such that a < b and f(a)* f(b) < 0.

Find the midpoint of a and b, say “t”

t is the root of the given function if f(t) = 0; else follow the next step.

Divide the interval [a, b]

If f(t)*f(b) <0, let a = t.

Else if f(t) *f(a), let b = t.

More items...

Step-by-step explanation:

Steps / Procedures for Bisection Method:

First, choose lower limit/guess (xL) and the upper limit (xU) for the root such that the function changes sign over the interval. ...

Solve for xR. ...

To get f(xL), substitute the value of xL to the given function. ...

Multiply the f(xL) and f(xR).

Answered by ashokshanu73
0

Answer:

After 7th iteration

-0.0721

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