Question

find a relation between 2 points xand y such that the point (x,y) is equidant from the from the points (7,-1) and (3'5)​

Answer 1

Answer:

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

$AP 2 =BP 2 (x−7) 2 +(y−1) 2 =(x−3) 2 +(y−5) 2 x 2 −14x+49+y 2 −2y+1=x 2 −6x+9+y 2 −10y+25$

x−y=2