Question

find a relation between a and b such that point (a,b) is equidistant from the points (8,3) and (2,7)

Answer 1

The distance between (8,3) and (a,b) is equal to the distance between (2,7) and (a,b)
√((8-a)^2 + (3-b)^2) = √((2-a)^2 + (7-b)^2)
On squaring both sides and simplifying we get,
73-53= -4a - 14b + 16a + 6b

20= 12a - 8b
This is equal to
3a- 2b = 5
Hope this helps.

Answer 2

Answer:

3a-2b =5

hope this would help...

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