find a relation between a and b such that point (a,b) is equidistant from the points (8,3) and (2,7)
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Answered by
131
The distance between (8,3) and (a,b) is equal to the distance between (2,7) and (a,b)
√((8-a)^2 + (3-b)^2) = √((2-a)^2 + (7-b)^2)
On squaring both sides and simplifying we get,
73-53= -4a - 14b + 16a + 6b
20= 12a - 8b
This is equal to
3a- 2b = 5
Hope this helps.
√((8-a)^2 + (3-b)^2) = √((2-a)^2 + (7-b)^2)
On squaring both sides and simplifying we get,
73-53= -4a - 14b + 16a + 6b
20= 12a - 8b
This is equal to
3a- 2b = 5
Hope this helps.
ranjanunique75oxetg0:
By solving the squares of two sides
Answered by
3
Answer:
3a-2b =5
hope this would help...
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