Question

Find a relation between j and q such that the point DD(j, q) is equidistant from the point RR(16,1) and KK(19,15)
Which of the following statement is correct ?
a]
28j + 6q - 329 = 0
b]
28j + 6q + 329 = 0
c]
6j + 28q - 329 = 0
d]6j + 28q + 329 = 0

Answer 1

Please use the right formula.

$\boxed{\text{ Section formula}}$ : $\sqrt{(x_1-x_2)^2+(y_1-y_2)^2 }$

→ $\textbf{Distance from DD to RR = Distance from DD to KK}$

• $\textbf{Distance from DD to RR is}$ $\sqrt{(j-16)^2+(q-1)^2}$

• $\textbf{Distance from DD to KK is}$ $\sqrt{(j-19)^2+(q-15)^2}$

Now,

→ $\sqrt{(j-16)^2+(q-1)^2}=\sqrt{(j-19)^2+(q-15)^2}$

→ $(j-16)^2+(q-1)^2=(j-19)^2+(q-15)^2$

→ $(j^2-32j+256)+(q^2-2q+1)=(j^2-38j+361)+(q^2-30q+225)$

→ $(6j-105)+(28q-224)=0$

→ $\text{\underline{6j + 28q - 329 = 0}}}$$\text{, which is option c}$

Answer 2

$\huge \tt \copyright \: 6j \: + \: 28q \: - 329 = 0$