Question

Find a relation between x & y such that the point P(x,y) is equidistant from the
points A(-5,3) and B(7,2).​

Answer 1

Answer:

this is your answer dear hope this answer help you.

Answer 2

Answer:

$\huge\star{\underline{mathtt{\pink{<u>Answer</u>}}}}\huge\star$

Distance between P(x,y) and B(−3,4)=PB=

Distance between P(x,y) and B(−3,4)=PB= (−3−x) 2 +(4−y) 2

EXPLINATION:

x= 2+6x+16+y

2−8y

Given, PA = PB

2x −6x+y

−6x+y 2−12y+45

x= 2+6x+y

= 2+6x+y 2−8y+25

=>x

=>x 2 −6x+y

=>x 2 −6x+y 2 −12y+45=x

12x+4y−20=0

12x+4y−20=03x+y−5=0.

.

I hop ethis helps you......