Question

Find a relation between x & y such that the point (x, y) is equidistant from the points A (- 3, 2) & B (4, - 5)​

Answer 1

Answer:

Distance between two points (x

1

,y

1

) and (x

2

,y

2

) can be calculated

using the formula

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Distance between P(x,y) and A(3,6)=PA=

(3−x)

2

+(6−y)

2

=

3

2

+x

2

−6x+6

2

+y

2

−12y

=

x

2

−6x+y

2

−12y+45

Distance between P(x,y) and B(−3,4)=PB=

(−3−x)

2

+(4−y)

2

=

9+x

2

+6x+16+y

2

−8y

=

x

2

+6x+y

2

−8y+25

Given, PA = PB

x

2

−6x+y

2

−12y+45

=

x

2

+6x+y

2

−8y+25

=>x

2

−6x+y

2

−12y+45=x

2

+6x+y

2

−8y+25

12x+4y−20=0

3x+y−5=0

Step-by-step explanation:

all steps are right