Question

Find a relation between x and y so that the point (x,y) is

equidistant from the points (-4,-4) and (-2,4) .​

Answer 1

Answer:

i hope this helps for you . . . . . . . .

Answer 2

Answer:

The relation between x and y is

x=-(4y+3)

Step-by-step explanation:

Let the given points be written as $A(-4,-4),B(-2,4)$ and $P(x,y)$

It is told that point P is equidistant from points A and B.

It can be mathematically denoted as $PA=PB$

The distance PA is

$PA=\sqrt{(-4-x)^2+(-4-y)^2}$

The distance PB is

$PB=\sqrt{(-2-x)^2+(4-y)^2}$

Equating both of these we get

$\sqrt{(-4-x)^2+(-4-y)^2}=\sqrt{(-2-x)^2+(4-y)^2}\\= > (-4-x)^2+(-4-y)^2=(-2-x)^2+(4-y)^2\\= > x^2+y^2+8x+8y+32=x^2+y^2+4x-8y+20\\= > 4x+16y+12=0\\= > x+4y+3=0\\= > x=-(4y+3)$

Therefore,

The relation between x and y is

x=-(4y+3)

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