Question

Find a relation between x and y such that point (x, y) is equidistant from the point (7,1) and (3,5).

Answer 1

Let us consider (X,Y)and (7,1)as AB
And(X Y) and (3,5) as CD
So,distance AB=distance CD
Then use the distance formula

Answer 2

A(X,Y) B(7,1) C(3,5)
AB =AC
AB^2 =AC^2
(7-x)^2 + (1-y)^2=(3-x)^2+(5-y)^2
49 +x^2 -14x+1+y^2 -2y =9+x^2-6x+25+y^2-10y
50-14x-2y=34-6x-10y
16-8x+8y=0
2-x+y=0

PLEASE SELECT MY ANSWERS AS BRAINLIEST