Question

. Find a relation between x and y such that the point P(x,y)

is equidistant from the points A(2,5) and B(-3,7)​

Answer 1

Answer:

( x-2)^2 + ( y -5)^2 = ( x+3)^2 + ( y -7)^2

x^2+4 - 4x +y^2+25-10y = x^2+9+6x +y^2 +49-14y

-4x -6x -10y + 14y +25 -49 +4 -9 = 0

-10x + 4y -29 = 0

10x -4y +29 = 0