Question

find a relation between X and Y such that the point P (X, Y) is equal distance from point A( 7,0) and B (0,5)​

Answer 1

There. is your ans ...

let P (x,y) be equidistant from the point A(7,0)and B(0,5)

PA =PB

Squaring both the side . we get

AP^2 =BP^2

# (x-7)^2 + (y-0)^2 = (x-0) ^2 + (y-5)^2

#. x^2 - 14x + 49 + y^2 = x^2 + y^2 + 25 -

10y

#. -14x +49 = 25 - 10y

#. - 14x +10y = 25 - 49

#. - 14x +10 y + 24 = 0

#. 14x - 10y - 24 =0

#. 2 ( 7x - 5y )= 24

#. 7x - 5y = 12

# 7x - 5y - 12= 0

which is required relation ....

I HOPE ITS HELP U

Answer 2

Answer:

7x - 5 y =12

upside ans wrong this is correct