Question

Find a relation between x and y such that the point (x, y) is equidistant from the
point (3,6) and (-3,4).​

Answer 1

Step-by-step explanation:

Let the point P(x,y) is equidistant from the points A(3,6)and B(−3,4)

∴PA=PB

By using the distance formula

√(x-3)²+(y-6)²= √(x+3)+(y-4)²

√x²-6x+9+y²-12y+36 = √x²+6x+9+y²-8y+16

after squaring both sides,we get

-6x+9-12y+36 = 6x+9-8y+16

-6x-12y+45 = 6x-8y+25

-6x-12y+45-6x+8y-25 = 0

3x+y-5=0

hence,this is the relation between x and y

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Answer 2

Answer:

⭐ur answer is in attachment ⭐

Step-by-step explanation:

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