Find a relation between x and y such that the point ( x, y ) is equidistant from
the points (6, 1) and (3,5).
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Step-by-step explanation:
Let P(x,y) be equidistant from the points A(7,1) and B(3,5).
AP=BP
AP
2
=BP
2
(x−7)
2
+(y−1)
2
=(x−3)
2
+(y−5)
2
x
2
−14x+49+y
2
−2y+1=x
2
−6x+9+y
2
−10y+25
x−y=2
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