find a relation between x and y such that the point (x, y) is equidistant from the point
3.6) and (-3, 4)
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Hii @malikhanzala501 ,
Answer:
Relation between x & y,
y = 5 - 3x or x = ( 5 - y ) / 3
Step-by-step explanation:
Let,
A ( x1 , y1 ) = ( 3 , 6 )
B ( x2 , y2 ) = ( -3 , 4 )
Let the point equidistant be,
O ( x , y )
As per the condition,
AO = BO
therefore, by squaring both sides,
AO² = BO²
Now, by distance formula,
=> ( x - 3 )² + ( y - 6 )² = ( x + 3 )² + ( y - 4 )²
=> x² + 9 - 6x + y² + 36 - 12y = x² + 9 + 6x + y² + 16 - 8y
=> - 6x - 12y + 45 = 6x - 8y + 25
=> 6x + 6x + 12y - 8y + 25 - 45 = 0
=> 12x + 4y - 20 = 0
=> 4 ( 3x + y - 5 ) = 0
=> 3x + y - 5 = 0
thus,
y = 5 - 3x or x = ( 5 - y ) / 3
Mark as Brianliest if this helped you!!!
Thank you!!!
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