Question

Find a relation between x and y such that the point (x,y) is equidistant from

(6,5) and (-4,3).​

Answer 1

Answer:

20x+4y-36=0

Step-by-step explanation:

to get a relation,

(x-6)²+(y-5)²=(x+4)²+(y-3)²

x²+36-12x+y²+25-10y=x²+16+8x+y²+9-6y

20x+4y-36=0