Question

Find a relation between x and y such that the point (x,y) is equidistant

from

(6,5) and (-4,3).​

Answer 1

Step-by-step explanation:

see the image for answer.

Answer 2

Answer:

Explanation:

Given :

• Points are A(6 , 5) and B(-4 , 3).

To Find :

• A relation between x and y.

Solution :

Let, P(x, y) be equidistant from the points

A(6 , 5) and B(-4 , 3).

.°. AP = PB

=> √(x - 6)² + (y - 5)² = √(x + 4)² + (y - 3)²

[ Squaring on both sides, we get ]

=> (x - 6)² + (y - 5)² = (x + 4)² + (y - 3)²

=> x² - 12x + 36 + y² - 10y + 25 = x² + 8x + 16 + y² - 6y + 9

=> -12x - 10y + 61 = 8x - 6y + 25

=> -12x - 8x - 10y + 6y = 25 - 61

=> -20x - 4y = -36

=> 20x + 4y = -36

=> 5x + y = -9

Hence :

A relation between x and y is 5x + y = -9.