Question

Find a relation between x and y such that the point (x , y) is equidistant from the points (7, 1) and (3, 5). [2] a) x - y = 2 b) x + y = 2 c) 2x - y = 2 d) x - 2y = ​

Answer 1

Answer:

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP

2

=BP

2

(x−7)

2

+(y−1)

2

=(x−3)

2

+(y−5)

2

x

2

−14x+49+y

2

−2y+1=x

2

−6x+9+y

2

−10y+25

x−y=2

Answer 2

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