Question

Find a relation between x and y such that the point (x,y ) is equidistant from the point (4,6) and (-3,5)​

Answer 1

Answer:

Find a relation between x and y such that the point (x,y ) is equidistant from the point (4,6) and (-3,5)

Step-by-step explanation:

Let the point P(x,y) is equidistant from the points A(3,6)and B(−3,4)

∴PA=PB

By using the distance formula

=(x2−x1)2+(y2−y1)2    we have

⇒(x−3)2+(y−6)2=(x+3)2+(y−4)2

⇒(x−3)2+(y−6)2=(x+3)2+(y−4)2

⇒x2−6x+9+y2−12y+36=x2+6x+9+y2−8y+16

⇒−6x−6x−12y+8y+36−16=0

⇒−12x−4y+20=0

⇒3x+y−5=0

Hence this is a relation between x and y.

IF U THINK MY ANSWER IS RIGHT THEN MAKE ME AS BRAINLIEST AND HAVING ANY DOUBT IN MY ANSWER THEN ASK YOUR FRIENDS

Answer 2

Step-by-step explanation:

X-4 y-5= x+3 y-6

Xy-5x-4y+20= xy+3y-6x-18

38=7y-x