Question

Find a relation between x and y such that the point (xy) is equidistant from the
points (-2,8) and (-3,-5)​

Answer 1

Answer:

y=13x+34

Step-by-step explanation:

Slope =-5-8/-3--2

=-13/-1

=13

y-8/x--2=13

y-8/x+2=13

y-8=13(x+2)

y-8=13x+26

y=13x+26+8

y=13x+34