Find a relation x and y if x,y 1,2 and 7,0 are collliner
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we can solve this by area formula
1/2[x1 [y2-y3] + x2 [y3-y1] + x3 [y1-y2] ] = 0 { as this points are colinear }
1/2[ x[2-0] +1[0-y] +7[y-2] ] =0
2x -y + 7y -14 = 0
2x -6y -14 =0
2[x-3y-7] = 0
hence relation is x - 3y - 7 = 0
1/2[x1 [y2-y3] + x2 [y3-y1] + x3 [y1-y2] ] = 0 { as this points are colinear }
1/2[ x[2-0] +1[0-y] +7[y-2] ] =0
2x -y + 7y -14 = 0
2x -6y -14 =0
2[x-3y-7] = 0
hence relation is x - 3y - 7 = 0
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